httpclient post请求
的有关信息介绍如下:最近做的项目要post 请求接口,所以就顺手写了个方法分享一下
打开MyEclipse工具,新建一个Test 类
然后编写post请求方法,代码如下:
public static String methodPost(String url,NameValuePair[] data){
String response= "";//要返回的response信息
HttpClient httpClient = new HttpClient();
PostMethod postMethod = new PostMethod(url);
// 将表单的值放入postMethod中
postMethod.setRequestBody(data);
// 执行postMethod
int statusCode = 0;
try {
statusCode = httpClient.executeMethod(postMethod);
} catch (HttpException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
// HttpClient对于要求接受后继服务的请求,象POST和PUT等不能自动处理转发
// 301或者302
if (statusCode == HttpStatus.SC_MOVED_PERMANENTLY
|| statusCode == HttpStatus.SC_MOVED_TEMPORARILY) {
// 从头中取出转向的地址
Header locationHeader = postMethod.getResponseHeader("location");
String location = null;
if (locationHeader != null) {
location = locationHeader.getValue();
System.out.println("页面跳转:" + location);
response= methodPost(location,data);//用跳转后的页面重新请求。
} else {
System.err.println("本地跳转失败路径为空.");
}
} else {
System.out.println(postMethod.getStatusLine());
try {
response= postMethod.getResponseBodyAsString();
} catch (IOException e) {
e.printStackTrace();
}
postMethod.releaseConnection();
}
return response;
}
在main 方法中编写测试代码,如下图